Is there any way to do VirtualDisk.OpenDisk() with a stream as input?

[NickHarmer]

The VirtualDisk class has static OpenDisk() methods which accept a file path as input. I have a use case where I don't necessarily know the disk type, but I only have a stream, not a file path.

Is there any way to use the convenience OpenDisk() method with a stream rather than a local file?

[LTRData]

The path based VirtualDisk.OpenDisk methods are based on recognizing image file format using file name extensions, not image file contents. Therefore, there is no similar detection logic for Stream based overloads, image file format needs to be determined already before that call.