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Define API for 32 bit valued functions #1
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Roman, can you provide more details? |
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Could you not do long h64 = hash64(...);
int h32 = (int) ((h64 >>> 32) | h64); |
@peter-lawrey yes, currently people do this. But this looks like the library's job. In the simplest case |
Should that be
I think you want bitwise exclusive OR, not bitwise OR |
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