Angular的post请求后台接受不了数据的解决方法

[Wscats]

方案1

加上这个模块，这里改写了**$httpProvider**服务

angular.module('MyModule', [], function($httpProvider) {
	// Use x-www-form-urlencoded Content-Type
	$httpProvider.defaults.headers.post['Content-Type'] = 'application/x-www-form-urlencoded;charset=utf-8';

	/**
	 * The workhorse; converts an object to x-www-form-urlencoded serialization.
	 * @param {Object} obj
	 * @return {String}
	 */
	var param = function(obj) {
		var query = '',
			name, value, fullSubName, subName, subValue, innerObj, i;

		for(name in obj) {
			value = obj[name];

			if(value instanceof Array) {
				for(i = 0; i < value.length; ++i) {
					subValue = value[i];
					fullSubName = name + '[' + i + ']';
					innerObj = {};
					innerObj[fullSubName] = subValue;
					query += param(innerObj) + '&';
				}
			} else if(value instanceof Object) {
				for(subName in value) {
					subValue = value[subName];
					fullSubName = name + '[' + subName + ']';
					innerObj = {};
					innerObj[fullSubName] = subValue;
					query += param(innerObj) + '&';
				}
			} else if(value !== undefined && value !== null)
				query += encodeURIComponent(name) + '=' + encodeURIComponent(value) + '&';
		}

		return query.length ? query.substr(0, query.length - 1) : query;
	};

	// Override $http service's default transformRequest
	$httpProvider.defaults.transformRequest = [function(data) {
		return angular.isObject(data) && String(data) !== '[object File]' ? param(data) : data;
	}];
});
var app = angular.module('wscat', ['MyModule']);
app.controller('loginCtrl', function($scope, $http) {
	$scope.name = 'wscat';
	$scope.submit = function() {
		$http.post('http://localhost/CI/myCi/index.php/login_api/login', {
			params: {
				username: $scope.username,
				password: $scope.password
			}
		}).success(function(data) {

		})
	}
})

更改前的数据格式为

更改过后数据格式为下图

我们就可以在后台获取数据了

public
    function login() {
    	$this -> load -> model('login_model');
        $data = array(
            'user_name' => $this->input->post('params')['username'],
            'password' => md5($this->input->post('params')['password'])
        );
        //or
        var_dump($_POST['params']);
    }

方案2

原因:可以发现传参方式是request payload，参数格式是json，而并非用的是form传参，所以在后台用接收form数据的方式接收参数就接收不到了

POST表单请求提交时，使用的Content-Type是application/x-www-form-urlencoded
而此处的Content-Type是:

解决:增添两段代码，代码如下;

$http({
	method: 'post',
	url: 'http://localhost:8081/search',
	data: {
		"page": page,
		"pageNum": pageNum
	},
	headers: { //1.设置类型
		'Content-Type': 'application/x-www-form-urlencoded;charset=utf-8'
	},
	transformRequest: function(obj) { //2.处理传递参数的格式
		var str = [];
		for(var p in obj) {
			str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p]))
		}
		return str.join('&')
	}
}).then(function(data) {

}, function(err) {

});

现在的谷歌监视为:

现在传参方式就变成form方式了，然后后端就可以正常接收参数了！

参考文档:Angular中的POST请求传递参数,服务端接收不到参数的解决方法