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控制台Scanner nextLine()获取用户输入执行报错 #115
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main函数不要加密 |
好的感谢 |
请问有用没有 我好想没解决 |
我 main 函数不加密也报错诶,是 exclude 不起作用么? |
检查密码是否正确,如果有报错查看对应文件的行数判断错误的原因,像上面截图的没有读到参数,可能就是没有读到密码,反射解密失败。一般来说 io.xjar ,main不可以加密 |
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package com.tool;
import java.util.Scanner;
public class App {
public static void main(String[] args) {
System.out.println("你好");//
Scanner scanner = new Scanner(System.in);
System.out.println(scanner.nextLine());
System.out.println(scanner.nextLine());
}
以上代码加密后执行就会报错
以下是加密和执行过程
public class App {
public static void main(String[] args) throws Exception {
XCryptos.encryption()
.from("D:\dev_lab\a_my_project\java\xjar-console-demo\target\xjar-console-demo-1.0-SNAPSHOT-jar-with-dependencies.jar")
.use("io.xjar")
.to("C:\Users\Administrator\Desktop\encrypted990.jar");
}
}
C:\Users\Administrator\Desktop>go build xjar.go
xjar.exe java -jar C:\Users\Administrator\Desktop\encrypted990.jar
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