Fix: use regexpp's default ecmaVersion in no-invalid-regexp (#13968)

eslint · Jan 1, 2021 · 83e98cd · 83e98cd
1 parent 7297363
commit 83e98cd
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Showing 2 changed files with 8 additions and 2 deletions.
diff --git a/lib/rules/no-invalid-regexp.js b/lib/rules/no-invalid-regexp.js
@@ -9,7 +9,7 @@
 //------------------------------------------------------------------------------
 
 const RegExpValidator = require("regexpp").RegExpValidator;
-const validator = new RegExpValidator({ ecmaVersion: 2018 });
+const validator = new RegExpValidator();
 const validFlags = /[gimuys]/gu;
 const undefined1 = void 0;
 

diff --git a/tests/lib/rules/no-invalid-regexp.js b/tests/lib/rules/no-invalid-regexp.js
@@ -41,7 +41,13 @@ ruleTester.run("no-invalid-regexp", rule, {
         { code: "new RegExp('(?<!a)b')", parserOptions: { ecmaVersion: 2018 } },
         { code: "new RegExp('(?<a>b)\\k<a>')", parserOptions: { ecmaVersion: 2018 } },
         { code: "new RegExp('(?<a>b)\\k<a>', 'u')", parserOptions: { ecmaVersion: 2018 } },
-        { code: "new RegExp('\\\\p{Letter}', 'u')", parserOptions: { ecmaVersion: 2018 } }
+        { code: "new RegExp('\\\\p{Letter}', 'u')", parserOptions: { ecmaVersion: 2018 } },
+
+        // ES2020
+        "new RegExp('(?<\\\\ud835\\\\udc9c>.)', 'g')",
+        "new RegExp('(?<\\\\u{1d49c}>.)', 'g')",
+        "new RegExp('(?<𝒜>.)', 'g');",
+        "new RegExp('\\\\p{Script=Nandinagari}', 'u');"
     ],
     invalid: [
         {