IPv6 IPSet difference returning v4-mapped result

[silverwind]

>>> import netaddr
>>> a = netaddr.IPSet()
>>> b = netaddr.IPSet()
>>> a.add("::/126")
>>> b.add("::/127")
>>> a.difference(b)
IPSet(['::0.0.0.2/127'])

Is the ::0.0.0.2/127 result expected? How would one get it into regular IPv6 format? I've tried ipnetwork.ipv6(ipv4_compatible=False) but it doesn't change it, unfortunately.

[snordhausen]

I get the expected IPSet(['::2/127']) on my system. I tested netaddr version 0.7.19 with Python 2.7 & netaddr 0.7.14 with Python 3.5, both on Linux. Which versions/OS are you using?

[silverwind]

I see the issue on macOs 10.12.4, Python 3.6.0, netAddr 0.7.19. On Linux with Python 3.6.0 and netAddr 0.7.19 it indeed works as expected.

Why is this stuff platform-dependant?

[Akasurde]

Same here - macOs 10.13.4, Python 3.6.4, netAddr 0.7.19

[jstasiak]

This is likely caused by inet_ntop working differently on Mac, see #82.