How can I InvokeNamed T to any

[iyaozhen]

Demo(use v2):

func TestInvokeAny(t *testing.T) {
	do.ProvideNamed(nil, "test", func(i do.Injector) (int, error) {
		return 1, nil
	})

	int1, err := do.InvokeNamed[int](nil, "test")
	if err != nil {
		t.Errorf("invoke error: %v", err)
		return
	}
	if int1 != 1 {
		t.Errorf("invoke response error: %v", int1)
		return
	}
	int2, err := do.InvokeNamed[any](nil, "test")
	if err != nil {
		t.Errorf("invoke error: %v", err)
		return
	}
	t.Log(int2)
}

do.InvokeNamed[any](nil, "test") not work

Why do I have to do this?

I want to generic call my local service, I just known service name

localService, err := do.InvokeNamed[any](nil, "ServiceName")
if err != nil {
return nil, err
}
methodValue := reflect.ValueOf(localService).MethodByName("FuncName")

invokeAnyByName Is what I want, can you Export It ?

thank you

[samber]

This is embarrassing. 🫣

Let me think about it.

[d-enk]

Аlso came across this

Seems to be solved by adding (Must)InvokeAsNamed to support not only any.

It just invokeAnyByName().(T), but with cast check in package

[samber]

I suppose do.InvokeNamed() should be able to skip the type check when the type is any ?

[iyaozhen]

I suppose do.InvokeNamed() should be able to skip the type check when the type is any ?

I think this is a good solution.

[samber]

@d-enk in your PR you said we might add the behavior to AsNamed. Can you tell us more about your though?

I don't see in what case we would declare an alias to any.

[d-enk]

I assumed. I just look at where invokeByName (type check) is used.

do/service_alias.go

Lines 78 to 79 in 1998a7a

	instance, err := invokeByName[Initial](s.scope, s.targetName)
	if err != nil {

No more reasons. Of course, it doesn't make sense until it's needed.

Thanks for the approval before 2.0

[samber]