I cann't understand. Use powershell in wsl to open the default？

[bigbigDreamer]

open/index.js

Line 123 in 7579417

} else if (platform === 'win32' || (isWsl && !isDocker())) {

command = isWsl ?
   `${mountPoint}c/Windows/System32/WindowsPowerShell/v1.0/powershell.exe` :
   `${process.env.SYSTEMROOT}\\System32\\WindowsPowerShell\\v1.0\\powershell`;

Now I modified the source file in node modules and used xdg-open can work normal.

Delete || (isWsl && !isDocker()), because wsl also is linux plateform.

But, Note: You should give your current wsl system login user root privileges.

#269

[bigbigDreamer]

In particular, you can install xdg-open in your wsl in advance.

$ sudo apt-get update 

$ sudo apt-get install xdg-open

Then, xdg-open can automatically open the default browser on your host machine, provided that you have sufficient permissions.

you can try edit the source code in open from node_modules:

if (app) {
	command = app;
} else {
	// When bundled by Webpack, there's no actual package file path and no local `xdg-open`.
	const isBundled = !__dirname || __dirname === '/';

	// Check if local `xdg-open` exists and is executable.
	let exeLocalXdgOpen = false;
	try {
			await fs.access(localXdgOpenPath, fsConstants.X_OK);
			exeLocalXdgOpen = true;
	} catch {}

		// const useSystemXdgOpen = process.versions.electron ||
		// 	platform === 'android' || isBundled || !exeLocalXdgOpen;
		// command = useSystemXdgOpen ? 'xdg-open' : localXdgOpenPath;
		command =  'xdg-open';
}

Finally，u can use as follow:

const open = require('open');

open(url, { wait: true })

Don't add app param!

[mklueh]

In my case, I have given WSL restricted access to the host machine intentionally to work as a sandbox. It still tries to access Powershell. What should I do?