Any expression being used as a condition must be able to evaluate as truthy or falsy in order to be considered "necessary". Conversely, any expression that always evaluates to truthy or always evaluates to falsy, as determined by the type of the expression, is considered unnecessary and will be flagged by this rule.
The following expressions are checked:
- Arguments to the
&&
,||
and?:
(ternary) operators - Conditions for
if
,for
,while
, anddo-while
statements.
Examples of incorrect code for this rule:
function head<T>(items: T[]) {
if (items) {
return items[0].toUpperCase();
}
}
const foo = 'foo';
if (foo) {
}
Examples of correct code for this rule:
function head<T>(items: T[]) {
if (items.length) {
return items[0].toUpperCase();
}
}
declare const foo: string;
// Necessary, since foo might be ''. (If undesired, consider using `strict-boolean-expressions` rule)
if (foo) {
}
Accepts an object with the following options:
ignoreRhs
(defaultfalse
) - doesn't check if the right-hand side of&&
and||
is a necessary condition. For example, the following code is valid with this option on:
function head<T>(items: T[]) {
return items.length && items[0].toUpperCase();
}
The main downside to using this rule is the need for type information.
- ESLint: no-constant-condition - this rule is essentially a stronger versison