check the note at the end of this README
Computing the square root of an integer or a fixed point integer into a fixed point integer. A fixed point is a 32 bit value with the decimal point between the bits 15 and 16, where bit 0 is the less significant bit of the value.
The functions sqrt_i32 and sqrt_i64 compute a simple integer square root.
The functions sqrt_i32_to_fx16_16 and sqrt_fx16_16_to_fx16_16 compute the
square root by using only 32 bit registers, addition, subtraction and
shifts.
When 64bit registers and operations are available, one can produce the same result by simply using the 64bit integer square root as shown below:
fx16_16_t sqrt_i32_to_fx16_16(int32_t v) {
return (fx16_16)sqrt_i64((int64_t)v << 32);
}
fx16_16_t sqrt_fx16_16_to_fx16_16(fx16_16_t v) {
return (fx16_16_t)sqrt_i64((int64_t)v << 16);
}We can thus compute the square root of a fixed point with any number of fractional bits. Below are examples for fixed point with 6 bit fractional part.
fx26_6 sqrt_i32_to_fx26_6(int32_t v) {
return (fx26_6)sqrt_i64((int64_t)v << 12);
}
fx26_6 sqrt_fx26_6_to_fx26_6(fx26_6 v) {
return (fx26_6)sqrt_i64((int64_t)v << 6);
}The main.c test the functions over a big range of values. To compile and
run it, use the command gcc *.c -lm -o fpsqrt && ./fpsqrt.
Algorithm and code Author: Christophe Meessen 1993.
Initially published in: usenet comp.lang.c, Thu, 28 Jan 1993 08:35:23 GMT,
Subject: Fixed point sqrt
by: Meessen Christophe
Ref: usenet post
Last update : May 21, 2021
The github user apodtele found a bug with the sqrt_fx16_16_to_fx16_16() function.
An overflow occurs when the input value is bigger or equal to 0x40000200.
The bug is now fixed with a slight performance penalty.