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Avoid cumbersome formatter workaround #6573
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If a list shouldn't be formatted with one element on each line, a single EOL-comment inside is enough to disable the formatter. Much simpler.
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RegExp(r' *0x([A-F0-9]{2}),? *\n? *'), (Match m) => '${m[1]}\n')) | ||
.map<int>((String b) => int.parse(b, radix: 16)) | ||
.toList(); | ||
]; |
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Another, still simpler than the original, workaround would be:
final String _imageBytesString =
'\x89\x50\x4E\x47\x0D\x0A\x1A\x0A\x00\x00\x00\x0D\x49'
'\x48\x44\x52\x00\x00\x00\x01\x00\x00\x00\x01\x08\x06'
'\x00\x00\x00\x1F\x15\xC4\x89\x00\x00\x00\x0A\x49\x44'
'\x41\x54\x78\x9C\x63\x00\x01\x00\x00\x05\x00\x01\x0D'
'\x0A\x2D\xB4\x00\x00\x00\x00\x49\x45\x4E\x44\xAE';
final List<int> _transparentImage = [..._imageBytesString.codeUnits];
Having a full, formatted string, and parsing it using RegExp, just to get to some bytes, feels a little like overkill.
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||
// Convert the string representing the hexidecimal bytes in the image into | ||
// a list of integers that can be consumed as image data in a stream. | ||
final List<int> _transparentImage = const LineSplitter() |
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Some possible improvements, for any similar code:
- For
const LineSplitter().convert(...)
, one can just useLineSplitter.split(...)
. - It's easier to just match the numbers, and then work on
allMatches
, than to try to remove what's not numbers:final List<int> _transparentImage = RegExp(r'0x([A-F0-9]{2})').allMatches(_imageBytesAsString) .map((b) => int.parse(b[1], radix: 16)) .toList();
If a list shouldn't be formatted with one element on each line, a single EOL-comment inside is enough to disable the formatter. Much simpler.