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Support docutils-0.18: Consume iterator of Element.traverse() #9780

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merged 1 commit into from Oct 26, 2021

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tk0miya
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@tk0miya tk0miya commented Oct 26, 2021

Feature or Bugfix

  • Refactoring

Purpose

  • Since 0.18, Element.traverse() returns an iterator instead of
    intermediate object. As a result, the return value is always considered
    as truthy value. And it becomes fragile when the caller modifies the
    doctree on the loop.
  • refs: Update Sphinx to work with docutils-0.18.x #9777

Since 0.18, Element.traverse() returns an iterator instead of
intermediate object.  As a result, the return value is always considered
as truthy value.  And it becomes fragile when the caller modifies the
doctree on the loop.
@tk0miya tk0miya added internals:refactoring docutils Tags upstream Docutils issues labels Oct 26, 2021
@tk0miya tk0miya added this to the 4.3.0 milestone Oct 26, 2021
@tk0miya tk0miya merged commit e719b82 into sphinx-doc:4.x Oct 26, 2021
@tk0miya tk0miya deleted the docutils-0.18_traverse branch October 26, 2021 17:02
@gmilde
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gmilde commented Nov 8, 2021

The reason for returning an iterator instead of a list is a considerable speedup in the majority of use cases. https://sourceforge.net/p/docutils/patches/160/
Be carful not to waste this gain by wrapping the return value in a list unless required.

If I get this right,

        doc = tree.traverse(nodes.document)[0]

just wants the first element that is of type "nodes.document".
Instead of traversing the complete tree, building a list of "document" nodes and picking the first

        doc = list(tree.traverse(nodes.document))[0]

one could use the iterators "next()" method:

        doc = tree.traverse(nodes.document).next()

(In cases where no matching node exists, the error returned would be
StopIteration instead of IndexError.)

or even simpler the next_node() method:

        doc = tree.next_node(nodes.document).next()

which returns the first matching node or None. (Note the different default of the optional argument "include_self".)

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