Fast and easy AJAX libraries for django applications.
3.x
2.x
Install django-ajax in your python environment
1- Download and install package:
$ pip install djangoajaxThrough Github:
pip install -e git://github.com/yceruto/django-ajax#egg=djangoajaxor simply with:
$ python setup.py install2- Add 'django_ajax' into the INSTALLED_APPS list.
3- Read usage section and enjoy this feature!
from django_ajax.decorators import ajax
@ajax
def my_view(request):
do_something()When the view does not return anything, you will receive this response (JSON format):
{"status": 200, "statusText": "OK", "content ": null}Sending content
@ajax
def my_view(request):
c = 2 + 3
return {'result': c}The whole result is converted into a JSON format as part of the content element:
{"status": 200, "statusText": "OK", "content": {"result": 5}}Combining with others decorators
from django.contrib.auth.decorators import login_required
from django_ajax.decorators import ajax
@ajax
@login_required
def my_view(request):
# if the request.user is anonymous then this view not proceed
return {'user_id': request.user.id}The location or path of the redirection response will be given in the content item, also the status and statusText will reflect what is going on:
{"status": 302, "statusText": "FOUND", "content": "/login"}Template response
from django.shortcuts import render
from django_ajax.decorators import ajax
@ajax
def my_view(request):
return render(request, 'home.html')The JSON response:
{"status": 200, "statusText": "OK", "content": "<html>...</html>"}Catch exceptions
@ajax
def my_view(request):
a = 23 / 0 # this line throws an exception
return aThe JSON response:
{"status": 500, "statusText": "INTERNAL SERVER ERROR", "content": "integer division or modulo by zero"}If you are using AJAX at all times in your project, we suggest you activate the AJAXMiddleware described below.
Add django_ajax.middleware.AJAXMiddleware to the MIDDLEWARE_CLASSES list in settings.py and all your responses will be converted to JSON whereas the request was made via AJAX, otherwise it will return a normal HttpResponse.
Caution
If this middleware is activated you cannot use the @ajax decorator. That will cause double JSON conversion.
AJAXMixin is an object that call to AJAX decorator.
from django.views.generic import TemplateView
from django_ajax.mixin import AJAXMixin
class SimpleView(AJAXMixin, TemplateView):
template_name = 'home.html'The JSON response:
{"status": 200, "statusText": "OK", "content": "<html>...</html>"}Enjoy And Share!